Base | Representation |
---|---|
bin | 1011110101010110111110… |
… | …1101011001001010101010 |
3 | 1201001212111222002202110201 |
4 | 2331111233231121022222 |
5 | 3201134201002010442 |
6 | 43401153400102414 |
7 | 2512015614061411 |
oct | 275255755311252 |
9 | 51055458082421 |
10 | 13011330110122 |
11 | 416708a708173 |
12 | 1561824164a0a |
13 | 734c6a0c39a6 |
14 | 32da74aa6478 |
15 | 1786c41d17b7 |
hex | bd56fb592aa |
13011330110122 has 4 divisors (see below), whose sum is σ = 19516995165186. Its totient is φ = 6505665055060.
The previous prime is 13011330110117. The next prime is 13011330110173. The reversal of 13011330110122 is 22101103311031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12798642195361 + 212687914761 = 3577519^2 + 461181^2 .
It is a super-2 number, since 2×130113301101222 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13011330110122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3252832527529 + ... + 3252832527532.
Almost surely, 213011330110122 is an apocalyptic number.
13011330110122 is a deficient number, since it is larger than the sum of its proper divisors (6505665055064).
13011330110122 is an equidigital number, since it uses as much as digits as its factorization.
13011330110122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6505665055063.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13011330110122 its reverse (22101103311031), we get a palindrome (35112433421153).
The spelling of 13011330110122 in words is "thirteen trillion, eleven billion, three hundred thirty million, one hundred ten thousand, one hundred twenty-two".
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