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1301133132311 = 9810611326251
BaseRepresentation
bin10010111011110001100…
…101000000001000010111
311121101110012112112112112
4102323301211000020113
5132304210040213221
62433422102341235
7163001202100205
oct22736145001027
94541405475475
101301133132311
11461897807281
12190202a2a81b
1395908aa8a2c
1446d91c70075
1523ca365315b
hex12ef1940217

1301133132311 has 4 divisors (see below), whose sum is σ = 1301135439624. Its totient is φ = 1301130825000.

The previous prime is 1301133132293. The next prime is 1301133132323. The reversal of 1301133132311 is 1132313311031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1301133132311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301133132371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317936 + ... + 1644186.

It is an arithmetic number, because the mean of its divisors is an integer number (325283859906).

Almost surely, 21301133132311 is an apocalyptic number.

1301133132311 is a deficient number, since it is larger than the sum of its proper divisors (2307313).

1301133132311 is an equidigital number, since it uses as much as digits as its factorization.

1301133132311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2307312.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1301133132311 its reverse (1132313311031), we get a palindrome (2433446443342).

The spelling of 1301133132311 in words is "one trillion, three hundred one billion, one hundred thirty-three million, one hundred thirty-two thousand, three hundred eleven".

Divisors: 1 981061 1326251 1301133132311