13011434301 has 8 divisors (see below), whose sum is σ = 17475211584. Its totient is φ = 8610973280.

The previous prime is 13011434291. The next prime is 13011434311. The reversal of 13011434301 is 10343411031.

It is an interprime number because it is at equal distance from previous prime (13011434291) and next prime (13011434311).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13011434301 - 2²¹ = 13009337149 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011434311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15828585 + ... + 15829406.

It is an arithmetic number, because the mean of its divisors is an integer number (2184401448).

Almost surely, 2^13011434301 is an apocalyptic number.

It is an amenable number.

13011434301 is a deficient number, since it is larger than the sum of its proper divisors (4463777283).

13011434301 is a wasteful number, since it uses less digits than its factorization.

13011434301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31658131.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13011434301 its reverse (10343411031), we get a palindrome (23354845332).

The spelling of 13011434301 in words is "thirteen billion, eleven million, four hundred thirty-four thousand, three hundred one".