Base | Representation |
---|---|
bin | 111100100101101101… |
… | …1001000111011010111 |
3 | 110102211220020121120120 |
4 | 1321023123020323113 |
5 | 4112433243041120 |
6 | 135435043403023 |
7 | 12254233234404 |
oct | 1711333107327 |
9 | 412756217516 |
10 | 130114424535 |
11 | 501aa222a67 |
12 | 21273083473 |
13 | c3677c8a64 |
14 | 64247732ab |
15 | 35b7e17140 |
hex | 1e4b6c8ed7 |
130114424535 has 16 divisors (see below), whose sum is σ = 208188213120. Its totient is φ = 69392648480.
The previous prime is 130114424467. The next prime is 130114424537. The reversal of 130114424535 is 535424411031.
It is not a de Polignac number, because 130114424535 - 218 = 130114162391 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130114424496 and 130114424505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130114424537) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 735796 + ... + 895334.
It is an arithmetic number, because the mean of its divisors is an integer number (13011763320).
Almost surely, 2130114424535 is an apocalyptic number.
130114424535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130114424535 is a deficient number, since it is larger than the sum of its proper divisors (78073788585).
130114424535 is a wasteful number, since it uses less digits than its factorization.
130114424535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213918.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 130114424535 its reverse (535424411031), we get a palindrome (665538835566).
The spelling of 130114424535 in words is "one hundred thirty billion, one hundred fourteen million, four hundred twenty-four thousand, five hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •