Base | Representation |
---|---|
bin | 1011110101010111101000… |
… | …0101010011110111001011 |
3 | 1201001212222002121000001121 |
4 | 2331111322011103313023 |
5 | 3201140030030331021 |
6 | 43401222534300111 |
7 | 2512023126313231 |
oct | 275257205236713 |
9 | 51055862530047 |
10 | 13011504152011 |
11 | 4167169980442 |
12 | 15618724b7637 |
13 | 734c9718c961 |
14 | 32da8dc4c951 |
15 | 1786d460e741 |
hex | bd57a153dcb |
13011504152011 has 8 divisors (see below), whose sum is σ = 13017007929600. Its totient is φ = 13006001459880.
The previous prime is 13011504151963. The next prime is 13011504152027. The reversal of 13011504152011 is 11025140511031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13011504152011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13011504152041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24171330 + ... + 24703768.
It is an arithmetic number, because the mean of its divisors is an integer number (1627125991200).
Almost surely, 213011504152011 is an apocalyptic number.
13011504152011 is a deficient number, since it is larger than the sum of its proper divisors (5503777589).
13011504152011 is an equidigital number, since it uses as much as digits as its factorization.
13011504152011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 542729.
The product of its (nonzero) digits is 600, while the sum is 25.
Adding to 13011504152011 its reverse (11025140511031), we get a palindrome (24036644663042).
The spelling of 13011504152011 in words is "thirteen trillion, eleven billion, five hundred four million, one hundred fifty-two thousand, eleven".
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