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130120110031212 = 223271923889367789
BaseRepresentation
bin11101100101011111110010…
…111011111100000101101100
3122001201100202012020001201100
4131211133302323330011230
5114023341441131444322
61140424204152443100
736256603425135540
oct3545376273740554
9561640665201640
10130120110031212
11385076a0985434
12127161956a9490
13577b3734b5b82
14241bbbdd87a20
151009ac9035dac
hex7657f2efc16c

130120110031212 has 216 divisors, whose sum is σ = 396831257440800. Its totient is φ = 35211328736256.

The previous prime is 130120110031151. The next prime is 130120110031217. The reversal of 130120110031212 is 212130011021031.

130120110031212 is a `hidden beast` number, since 1 + 301 + 20 + 1 + 100 + 31 + 212 = 666.

It is a super-2 number, since 2×1301201100312122 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (130120110031217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 353606214 + ... + 353974002.

Almost surely, 2130120110031212 is an apocalyptic number.

130120110031212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130120110031212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (198415628720400).

130120110031212 is an abundant number, since it is smaller than the sum of its proper divisors (266711147409588).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130120110031212 is a wasteful number, since it uses less digits than its factorization.

130120110031212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 371733 (or 371709 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 130120110031212 its reverse (212130011021031), we get a palindrome (342250121052243).

The spelling of 130120110031212 in words is "one hundred thirty trillion, one hundred twenty billion, one hundred ten million, thirty-one thousand, two hundred twelve".