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130122204441 = 343374068147
BaseRepresentation
bin111100100101111100…
…0110100010100011001
3110102212102212212121020
41321023320310110121
54112442241020231
6135435522233053
712254356326345
oct1711370642431
9412772785536
10130122204441
1150203657139
12212757b5789
13c3692c0c58
1464257da625
1535b8952396
hex1e4be34519

130122204441 has 4 divisors (see below), whose sum is σ = 173496272592. Its totient is φ = 86748136292.

The previous prime is 130122204371. The next prime is 130122204517. The reversal of 130122204441 is 144402221031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130122204441 - 214 = 130122188057 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130122205441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21687034071 + ... + 21687034076.

It is an arithmetic number, because the mean of its divisors is an integer number (43374068148).

Almost surely, 2130122204441 is an apocalyptic number.

It is an amenable number.

130122204441 is a deficient number, since it is larger than the sum of its proper divisors (43374068151).

130122204441 is an equidigital number, since it uses as much as digits as its factorization.

130122204441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43374068150.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 130122204441 its reverse (144402221031), we get a palindrome (274524425472).

The spelling of 130122204441 in words is "one hundred thirty billion, one hundred twenty-two million, two hundred four thousand, four hundred forty-one".

Divisors: 1 3 43374068147 130122204441