Search a number
-
+
13012254500 = 2253719419467
BaseRepresentation
bin11000001111001011…
…10011111100100100
31020120211212000110212
430013211303330210
5203122114121000
65551105434552
7640312224020
oct140745637444
936524760425
1013012254500
115578095443
12263193ba58
1312c4aa279b
148b6239380
15512572c35
hex307973f24

13012254500 has 192 divisors, whose sum is σ = 34342963200. Its totient is φ = 4207420800.

The previous prime is 13012254473. The next prime is 13012254509. The reversal of 13012254500 is 545221031.

It is not an unprimeable number, because it can be changed into a prime (13012254509) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27863267 + ... + 27863733.

It is an arithmetic number, because the mean of its divisors is an integer number (178869600).

Almost surely, 213012254500 is an apocalyptic number.

13012254500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13012254500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17171481600).

13012254500 is an abundant number, since it is smaller than the sum of its proper divisors (21330708700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13012254500 is a wasteful number, since it uses less digits than its factorization.

13012254500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 931 (or 919 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 13012254500 its reverse (545221031), we get a palindrome (13557475531).

The spelling of 13012254500 in words is "thirteen billion, twelve million, two hundred fifty-four thousand, five hundred".