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130123089540515 = 526024617908103
BaseRepresentation
bin11101100101100010100100…
…100001110111010110100011
3122001201122102211200211002202
4131211202210201313112203
5114023414041410244030
61140425415550003415
736260040314426561
oct3545424441672643
9561648384624082
10130123089540515
113850898a81a915
12127168874a656b
13577b729874826
14241bdc3978a31
151009c008cd745
hex7658a48775a3

130123089540515 has 4 divisors (see below), whose sum is σ = 156147707448624. Its totient is φ = 104098471632408.

The previous prime is 130123089540511. The next prime is 130123089540517. The reversal of 130123089540515 is 515045980321031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130123089540515 - 22 = 130123089540511 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130123089540515.

It is not an unprimeable number, because it can be changed into a prime (130123089540511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13012308954047 + ... + 13012308954056.

It is an arithmetic number, because the mean of its divisors is an integer number (39036926862156).

Almost surely, 2130123089540515 is an apocalyptic number.

130123089540515 is a deficient number, since it is larger than the sum of its proper divisors (26024617908109).

130123089540515 is an equidigital number, since it uses as much as digits as its factorization.

130123089540515 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26024617908108.

The product of its (nonzero) digits is 648000, while the sum is 47.

The spelling of 130123089540515 in words is "one hundred thirty trillion, one hundred twenty-three billion, eighty-nine million, five hundred forty thousand, five hundred fifteen".

Divisors: 1 5 26024617908103 130123089540515