13012314433 has 4 divisors (see below), whose sum is σ = 13050926980. Its totient is φ = 12973701888.

The previous prime is 13012314397. The next prime is 13012314467. The reversal of 13012314433 is 33441321031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1794962689 + 11217351744 = 42367^2 + 105912^2 .

It is a cyclic number.

It is not a de Polignac number, because 13012314433 - 2²⁹ = 12475443521 is a prime.

It is a super-2 number, since 2×13012314433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13012314398 and 13012314407.

It is not an unprimeable number, because it can be changed into a prime (13012314493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19305768 + ... + 19306441.

It is an arithmetic number, because the mean of its divisors is an integer number (3262731745).

Almost surely, 2^13012314433 is an apocalyptic number.

It is an amenable number.

13012314433 is a deficient number, since it is larger than the sum of its proper divisors (38612547).

13012314433 is an equidigital number, since it uses as much as digits as its factorization.

13012314433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38612546.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13012314433 its reverse (33441321031), we get a palindrome (46453635464).

The spelling of 13012314433 in words is "thirteen billion, twelve million, three hundred fourteen thousand, four hundred thirty-three".