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130124433235 = 526024886647
BaseRepresentation
bin111100100110000000…
…1010100011101010011
3110102212121002002221011
41321030001110131103
54112443323330420
6135440042111351
712254414301316
oct1711401243523
9412777062834
10130124433235
1150204939715
12212764ab557
13c3698c1574
146425c1a97d
1535b8c4295a
hex1e4c054753

130124433235 has 4 divisors (see below), whose sum is σ = 156149319888. Its totient is φ = 104099546584.

The previous prime is 130124433227. The next prime is 130124433251. The reversal of 130124433235 is 532334421031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130124433235 - 23 = 130124433227 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130124433197 and 130124433206.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13012443319 + ... + 13012443328.

It is an arithmetic number, because the mean of its divisors is an integer number (39037329972).

Almost surely, 2130124433235 is an apocalyptic number.

130124433235 is a deficient number, since it is larger than the sum of its proper divisors (26024886653).

130124433235 is an equidigital number, since it uses as much as digits as its factorization.

130124433235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26024886652.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 130124433235 its reverse (532334421031), we get a palindrome (662458854266).

The spelling of 130124433235 in words is "one hundred thirty billion, one hundred twenty-four million, four hundred thirty-three thousand, two hundred thirty-five".

Divisors: 1 5 26024886647 130124433235