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1301312112314 = 2650656056157
BaseRepresentation
bin10010111011111100001…
…111110000011010111010
311121101220200022122221112
4102323330033300122322
5132310041400043224
62433451534440322
7163005504306614
oct22737417603272
94541820278845
101301312112314
11461979842635
121902529630a2
1395936bb3566
1446dab93ddb4
1523cb420930e
hex12efc3f06ba

1301312112314 has 4 divisors (see below), whose sum is σ = 1951968168474. Its totient is φ = 650656056156.

The previous prime is 1301312112313. The next prime is 1301312112473. The reversal of 1301312112314 is 4132112131031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 886672706689 + 414639405625 = 941633^2 + 643925^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 1301312112314.

It is not an unprimeable number, because it can be changed into a prime (1301312112313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325328028077 + ... + 325328028080.

Almost surely, 21301312112314 is an apocalyptic number.

1301312112314 is a deficient number, since it is larger than the sum of its proper divisors (650656056160).

1301312112314 is an equidigital number, since it uses as much as digits as its factorization.

1301312112314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 650656056159.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1301312112314 its reverse (4132112131031), we get a palindrome (5433424243345).

The spelling of 1301312112314 in words is "one trillion, three hundred one billion, three hundred twelve million, one hundred twelve thousand, three hundred fourteen".

Divisors: 1 2 650656056157 1301312112314