1301323000101 has 4 divisors (see below), whose sum is σ = 1735097333472. Its totient is φ = 867548666732.

The previous prime is 1301323000099. The next prime is 1301323000139. The reversal of 1301323000101 is 1010003231031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301323000101 - 2¹ = 1301323000099 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301323000151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216887166681 + ... + 216887166686.

It is an arithmetic number, because the mean of its divisors is an integer number (433774333368).

Almost surely, 2^{1301323000101} is an apocalyptic number.

It is an amenable number.

1301323000101 is a deficient number, since it is larger than the sum of its proper divisors (433774333371).

1301323000101 is an equidigital number, since it uses as much as digits as its factorization.

1301323000101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433774333370.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1301323000101 its reverse (1010003231031), we get a palindrome (2311326231132).

The spelling of 1301323000101 in words is "one trillion, three hundred one billion, three hundred twenty-three million, one hundred one", and thus it is an aban number.