Base | Representation |
---|---|
bin | 11101100101101100000101… |
… | …111010111010101101010011 |
3 | 122001202121211100202100011021 |
4 | 131211230011322322231103 |
5 | 114024101011214314103 |
6 | 1140434230251300311 |
7 | 36260551551164551 |
oct | 3545540572725523 |
9 | 561677740670137 |
10 | 130133313432403 |
11 | 38512256956146 |
12 | 1271885b44a697 |
13 | 577c698a62cb8 |
14 | 241c6b373cbd1 |
15 | 100a0ed264bbd |
hex | 765b05ebab53 |
130133313432403 has 16 divisors (see below), whose sum is σ = 132199327817856. Its totient is φ = 128075015799360.
The previous prime is 130133313432391. The next prime is 130133313432413. The reversal of 130133313432403 is 304234313331031.
It is a cyclic number.
It is not a de Polignac number, because 130133313432403 - 237 = 129995874478931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130133313432413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 329665876 + ... + 330060382.
It is an arithmetic number, because the mean of its divisors is an integer number (8262457988616).
Almost surely, 2130133313432403 is an apocalyptic number.
130133313432403 is a deficient number, since it is larger than the sum of its proper divisors (2066014385453).
130133313432403 is an equidigital number, since it uses as much as digits as its factorization.
130133313432403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 404274.
The product of its (nonzero) digits is 69984, while the sum is 34.
Adding to 130133313432403 its reverse (304234313331031), we get a palindrome (434367626763434).
The spelling of 130133313432403 in words is "one hundred thirty trillion, one hundred thirty-three billion, three hundred thirteen million, four hundred thirty-two thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •