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130134935 = 572531163
BaseRepresentation
bin1111100000110…
…11001110010111
3100001212112120102
413300123032113
5231303304220
620525124315
73140062100
oct760331627
9301775512
10130134935
1167504337
12376b969b
1320c65028
14133d73a7
15b658775
hex7c1b397

130134935 has 12 divisors (see below), whose sum is σ = 181658088. Its totient is φ = 89235216.

The previous prime is 130134929. The next prime is 130134941. The reversal of 130134935 is 539431031.

It is an interprime number because it is at equal distance from previous prime (130134929) and next prime (130134941).

It is not a de Polignac number, because 130134935 - 26 = 130134871 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130134898 and 130134907.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 265337 + ... + 265826.

It is an arithmetic number, because the mean of its divisors is an integer number (15138174).

Almost surely, 2130134935 is an apocalyptic number.

130134935 is a deficient number, since it is larger than the sum of its proper divisors (51523153).

130134935 is an equidigital number, since it uses as much as digits as its factorization.

130134935 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 531182 (or 531175 counting only the distinct ones).

The product of its (nonzero) digits is 4860, while the sum is 29.

The square root of 130134935 is about 11407.6700074993. The cubic root of 130134935 is about 506.7549113861.

Adding to 130134935 its reverse (539431031), we get a palindrome (669565966).

The spelling of 130134935 in words is "one hundred thirty million, one hundred thirty-four thousand, nine hundred thirty-five".

Divisors: 1 5 7 35 49 245 531163 2655815 3718141 18590705 26026987 130134935