Base | Representation |
---|---|
bin | 11101100101101110000001… |
… | …010011101101111000010111 |
3 | 122001202211011122000020121211 |
4 | 131211232001103231320113 |
5 | 114024114231140443111 |
6 | 1140435211520522251 |
7 | 36260654055553534 |
oct | 3545560123557027 |
9 | 561684148006554 |
10 | 130135383531031 |
11 | 3851311942095a |
12 | 12719138780387 |
13 | 577c9388b1a28 |
14 | 241c82c643d8b |
15 | 100a1bed72521 |
hex | 765b814ede17 |
130135383531031 has 4 divisors (see below), whose sum is σ = 130135442218992. Its totient is φ = 130135324843072.
The previous prime is 130135383531017. The next prime is 130135383531089.
130135383531031 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130135383531031 - 219 = 130135383006743 is a prime.
It is a super-2 number, since 2×1301353835310312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130135383531331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25881691 + ... + 30498076.
It is an arithmetic number, because the mean of its divisors is an integer number (32533860554748).
Almost surely, 2130135383531031 is an apocalyptic number.
130135383531031 is a deficient number, since it is larger than the sum of its proper divisors (58687961).
130135383531031 is an equidigital number, since it uses as much as digits as its factorization.
130135383531031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58687960.
The product of its (nonzero) digits is 145800, while the sum is 40.
The spelling of 130135383531031 in words is "one hundred thirty trillion, one hundred thirty-five billion, three hundred eighty-three million, five hundred thirty-one thousand, thirty-one".
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