Base | Representation |
---|---|
bin | 11000001111010101… |
… | …10001001101111101 |
3 | 1020120221022001010011 |
4 | 30013222301031331 |
5 | 203122432212140 |
6 | 5551153343221 |
7 | 640326245542 |
oct | 140752611575 |
9 | 36527261104 |
10 | 13013554045 |
11 | 55788a2848 |
12 | 2632267b11 |
13 | 12c513914b |
14 | 8b6496bc9 |
15 | 51272ccea |
hex | 307ab137d |
13013554045 has 4 divisors (see below), whose sum is σ = 15616264860. Its totient is φ = 10410843232.
The previous prime is 13013554033. The next prime is 13013554093. The reversal of 13013554045 is 54045531031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8838068121 + 4175485924 = 94011^2 + 64618^2 .
It is a cyclic number.
It is not a de Polignac number, because 13013554045 - 221 = 13011456893 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13013553998 and 13013554016.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1301355400 + ... + 1301355409.
It is an arithmetic number, because the mean of its divisors is an integer number (3904066215).
Almost surely, 213013554045 is an apocalyptic number.
It is an amenable number.
13013554045 is a deficient number, since it is larger than the sum of its proper divisors (2602710815).
13013554045 is an equidigital number, since it uses as much as digits as its factorization.
13013554045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2602710814.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 13013554045 in words is "thirteen billion, thirteen million, five hundred fifty-four thousand, forty-five".
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