Base | Representation |
---|---|
bin | 11101100101110011101000… |
… | …001011101000111010110111 |
3 | 122001210101201020101210220220 |
4 | 131211303220023220322313 |
5 | 114024214044013342403 |
6 | 1140442045201425423 |
7 | 36261256215442026 |
oct | 3545635013507267 |
9 | 561711636353826 |
10 | 130141404434103 |
11 | 38515729029507 |
12 | 1271a33903b273 |
13 | 57803880b8c7a |
14 | 241cc401348bd |
15 | 100a423738953 |
hex | 765ce82e8eb7 |
130141404434103 has 8 divisors (see below), whose sum is σ = 173522031158400. Its totient is φ = 86760856999608.
The previous prime is 130141404434101. The next prime is 130141404434113. The reversal of 130141404434103 is 301434404141031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130141404434103 - 21 = 130141404434101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130141404434101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15880683 + ... + 22637996.
It is an arithmetic number, because the mean of its divisors is an integer number (21690253894800).
Almost surely, 2130141404434103 is an apocalyptic number.
130141404434103 is a deficient number, since it is larger than the sum of its proper divisors (43380626724297).
130141404434103 is a wasteful number, since it uses less digits than its factorization.
130141404434103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39644901.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 130141404434103 its reverse (301434404141031), we get a palindrome (431575808575134).
The spelling of 130141404434103 in words is "one hundred thirty trillion, one hundred forty-one billion, four hundred four million, four hundred thirty-four thousand, one hundred three".
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