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13014333044111 = 76193003538667
BaseRepresentation
bin1011110101100010001010…
…1100101011010110001111
31201002011021020122121111002
42331120202230223112033
53201211323224402421
643402411351250515
72512153206434120
oct275304254532617
951064236577432
1013014333044111
1141683907a19a3
121562321979a3b
137353282947c9
1432dc7b834047
151787ecb54b0b
hexbd622b2b58f

13014333044111 has 8 divisors (see below), whose sum is σ = 14897551793280. Its totient is φ = 11137121373528.

The previous prime is 13014333044099. The next prime is 13014333044113. The reversal of 13014333044111 is 11144033341031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13014333044111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13014333044113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1501765001 + ... + 1501773666.

It is an arithmetic number, because the mean of its divisors is an integer number (1862193974160).

Almost surely, 213014333044111 is an apocalyptic number.

13014333044111 is a deficient number, since it is larger than the sum of its proper divisors (1883218749169).

13014333044111 is an equidigital number, since it uses as much as digits as its factorization.

13014333044111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3003539293.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13014333044111 its reverse (11144033341031), we get a palindrome (24158366385142).

The spelling of 13014333044111 in words is "thirteen trillion, fourteen billion, three hundred thirty-three million, forty-four thousand, one hundred eleven".

Divisors: 1 7 619 4333 3003538667 21024770669 1859190434873 13014333044111