13014451433 has 16 divisors (see below), whose sum is σ = 13265683200. Its totient is φ = 12766170240.

The previous prime is 13014451361. The next prime is 13014451441. The reversal of 13014451433 is 33415441031.

It is a happy number.

13014451433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13014451433 - 2¹⁶ = 13014385897 is a prime.

It is a super-2 number, since 2×13014451433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13014451396 and 13014451405.

It is not an unprimeable number, because it can be changed into a prime (13014451733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6529085 + ... + 6531077.

It is an arithmetic number, because the mean of its divisors is an integer number (829105200).

Almost surely, 2^13014451433 is an apocalyptic number.

It is an amenable number.

13014451433 is a deficient number, since it is larger than the sum of its proper divisors (251231767).

13014451433 is a wasteful number, since it uses less digits than its factorization.

13014451433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2672.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 13014451433 its reverse (33415441031), we get a palindrome (46429892464).

The spelling of 13014451433 in words is "thirteen billion, fourteen million, four hundred fifty-one thousand, four hundred thirty-three".