Base | Representation |
---|---|
bin | 1011110101100101100011… |
… | …1010001010110100000111 |
3 | 1201002020121122001022202012 |
4 | 2331121120322022310013 |
5 | 3201220204043104120 |
6 | 43403041521204435 |
7 | 2512214562215261 |
oct | 275313072126407 |
9 | 51066548038665 |
10 | 13015242550535 |
11 | 41688081275a5 |
12 | 156253649071b |
13 | 7354418391a4 |
14 | 32dd26546b31 |
15 | 17885290d1c5 |
hex | bd658e8ad07 |
13015242550535 has 16 divisors (see below), whose sum is σ = 15883188026400. Its totient is φ = 10235600067456.
The previous prime is 13015242550517. The next prime is 13015242550573. The reversal of 13015242550535 is 53505524251031.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13015242550535 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13015242550492 and 13015242550501.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33504437 + ... + 33890673.
It is an arithmetic number, because the mean of its divisors is an integer number (992699251650).
Almost surely, 213015242550535 is an apocalyptic number.
13015242550535 is a deficient number, since it is larger than the sum of its proper divisors (2867945475865).
13015242550535 is a wasteful number, since it uses less digits than its factorization.
13015242550535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 500530.
The product of its (nonzero) digits is 450000, while the sum is 41.
The spelling of 13015242550535 in words is "thirteen trillion, fifteen billion, two hundred forty-two million, five hundred fifty thousand, five hundred thirty-five".
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