Base | Representation |
---|---|
bin | 111100100111001111… |
… | …0010101001001101001 |
3 | 110102222110112020002002 |
4 | 1321032132111021221 |
5 | 4113034342431211 |
6 | 135444112220345 |
7 | 12255424165565 |
oct | 1711636251151 |
9 | 412873466062 |
10 | 130165592681 |
11 | 502260a1393 |
12 | 2128823a6b5 |
13 | c3752a2a77 |
14 | 642b4926a5 |
15 | 35bc67303b |
hex | 1e4e795269 |
130165592681 has 4 divisors (see below), whose sum is σ = 130396793232. Its totient is φ = 129934392132.
The previous prime is 130165592663. The next prime is 130165592693. The reversal of 130165592681 is 186295561031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 130165592681 - 26 = 130165592617 is a prime.
It is a super-2 number, since 2×1301655926812 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130165592611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115599431 + ... + 115600556.
It is an arithmetic number, because the mean of its divisors is an integer number (32599198308).
Almost surely, 2130165592681 is an apocalyptic number.
It is an amenable number.
130165592681 is a deficient number, since it is larger than the sum of its proper divisors (231200551).
130165592681 is an equidigital number, since it uses as much as digits as its factorization.
130165592681 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 231200550.
The product of its (nonzero) digits is 388800, while the sum is 47.
The spelling of 130165592681 in words is "one hundred thirty billion, one hundred sixty-five million, five hundred ninety-two thousand, six hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •