Search a number
-
+
130165592681 = 563231199987
BaseRepresentation
bin111100100111001111…
…0010101001001101001
3110102222110112020002002
41321032132111021221
54113034342431211
6135444112220345
712255424165565
oct1711636251151
9412873466062
10130165592681
11502260a1393
122128823a6b5
13c3752a2a77
14642b4926a5
1535bc67303b
hex1e4e795269

130165592681 has 4 divisors (see below), whose sum is σ = 130396793232. Its totient is φ = 129934392132.

The previous prime is 130165592663. The next prime is 130165592693. The reversal of 130165592681 is 186295561031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130165592681 - 26 = 130165592617 is a prime.

It is a super-2 number, since 2×1301655926812 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130165592611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115599431 + ... + 115600556.

It is an arithmetic number, because the mean of its divisors is an integer number (32599198308).

Almost surely, 2130165592681 is an apocalyptic number.

It is an amenable number.

130165592681 is a deficient number, since it is larger than the sum of its proper divisors (231200551).

130165592681 is an equidigital number, since it uses as much as digits as its factorization.

130165592681 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231200550.

The product of its (nonzero) digits is 388800, while the sum is 47.

The spelling of 130165592681 in words is "one hundred thirty billion, one hundred sixty-five million, five hundred ninety-two thousand, six hundred eighty-one".

Divisors: 1 563 231199987 130165592681