Base | Representation |
---|---|
bin | 111100100111111100… |
… | …0000001010100111111 |
3 | 110110001002202202011020 |
4 | 1321033320001110333 |
5 | 4113111402320242 |
6 | 135450312155223 |
7 | 12256131062163 |
oct | 1711770012477 |
9 | 413032682136 |
10 | 130189104447 |
11 | 502383a00a6 |
12 | 21294098b13 |
13 | c37a11575c |
14 | 6430652ca3 |
15 | 35be7696ec |
hex | 1e4fe0153f |
130189104447 has 4 divisors (see below), whose sum is σ = 173585472600. Its totient is φ = 86792736296.
The previous prime is 130189104439. The next prime is 130189104457. The reversal of 130189104447 is 744401981031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 744401981031 = 3 ⋅248133993677.
It is a cyclic number.
It is not a de Polignac number, because 130189104447 - 23 = 130189104439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130189104399 and 130189104408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130189104457) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21698184072 + ... + 21698184077.
It is an arithmetic number, because the mean of its divisors is an integer number (43396368150).
Almost surely, 2130189104447 is an apocalyptic number.
130189104447 is a deficient number, since it is larger than the sum of its proper divisors (43396368153).
130189104447 is an equidigital number, since it uses as much as digits as its factorization.
130189104447 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43396368152.
The product of its (nonzero) digits is 96768, while the sum is 42.
The spelling of 130189104447 in words is "one hundred thirty billion, one hundred eighty-nine million, one hundred four thousand, four hundred forty-seven".
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