13020000441341 has 4 divisors (see below), whose sum is σ = 13020032769372. Its totient is φ = 13019968113312.

The previous prime is 13020000441289. The next prime is 13020000441361. The reversal of 13020000441341 is 14314400002031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7553405735716 + 5466594705625 = 2748346^2 + 2338075^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13020000441341 is a prime.

It is a super-2 number, since 2×13020000441341² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13020000441361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15552176 + ... + 16367961.

It is an arithmetic number, because the mean of its divisors is an integer number (3255008192343).

Almost surely, 2^{13020000441341} is an apocalyptic number.

It is an amenable number.

13020000441341 is a deficient number, since it is larger than the sum of its proper divisors (32328031).

13020000441341 is an equidigital number, since it uses as much as digits as its factorization.

13020000441341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32328030.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13020000441341 its reverse (14314400002031), we get a palindrome (27334400443372).

The spelling of 13020000441341 in words is "thirteen trillion, twenty billion, four hundred forty-one thousand, three hundred forty-one".