Base | Representation |
---|---|
bin | 1011110101110111010010… |
… | …0110110101100100011001 |
3 | 1201002200220100012011222122 |
4 | 2331131310212311210121 |
5 | 3201304431031241441 |
6 | 43405150105231025 |
7 | 2512443535530542 |
oct | 275356446654431 |
9 | 51080810164878 |
10 | 13020002212121 |
11 | 416a82a8aa813 |
12 | 1563444492475 |
13 | 735a1c958ba8 |
14 | 3302587254c9 |
15 | 178a306dd34b |
hex | bd7749b5919 |
13020002212121 has 4 divisors (see below), whose sum is σ = 13020121756452. Its totient is φ = 13019882667792.
The previous prime is 13020002212097. The next prime is 13020002212249. The reversal of 13020002212121 is 12121220002031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7366121683600 + 5653880528521 = 2714060^2 + 2377789^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13020002212121 is a prime.
It is a super-3 number, since 3×130200022121213 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13020002212121.
It is not an unprimeable number, because it can be changed into a prime (13020002211121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59608646 + ... + 59826671.
It is an arithmetic number, because the mean of its divisors is an integer number (3255030439113).
Almost surely, 213020002212121 is an apocalyptic number.
It is an amenable number.
13020002212121 is a deficient number, since it is larger than the sum of its proper divisors (119544331).
13020002212121 is a wasteful number, since it uses less digits than its factorization.
13020002212121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119544330.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 13020002212121 its reverse (12121220002031), we get a palindrome (25141222214152).
The spelling of 13020002212121 in words is "thirteen trillion, twenty billion, two million, two hundred twelve thousand, one hundred twenty-one".
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