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130201202031 = 343400400677
BaseRepresentation
bin111100101000010011…
…0001010110101101111
3110110001221112100220220
41321100212022311233
54113123001431111
6135451423342423
712256335646125
oct1712046126557
9413057470826
10130201202031
11502442031aa
1221298151a13
13c37c78cca4
1464320c1915
1535c0858e06
hex1e5098ad6f

130201202031 has 4 divisors (see below), whose sum is σ = 173601602712. Its totient is φ = 86800801352.

The previous prime is 130201201997. The next prime is 130201202039. The reversal of 130201202031 is 130202102031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130201202031 - 26 = 130201201967 is a prime.

It is a super-2 number, since 2×1302012020312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130201202031.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130201202039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21700200336 + ... + 21700200341.

It is an arithmetic number, because the mean of its divisors is an integer number (43400400678).

Almost surely, 2130201202031 is an apocalyptic number.

130201202031 is a deficient number, since it is larger than the sum of its proper divisors (43400400681).

130201202031 is an equidigital number, since it uses as much as digits as its factorization.

130201202031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43400400680.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 130201202031 its reverse (130202102031), we get a palindrome (260403304062).

The spelling of 130201202031 in words is "one hundred thirty billion, two hundred one million, two hundred two thousand, thirty-one".

Divisors: 1 3 43400400677 130201202031