Search a number
-
+
130202002023 = 343400667341
BaseRepresentation
bin111100101000010100…
…1001110001001100111
3110110002000001000022020
41321100221032021213
54113123203031043
6135451452434223
712256345520352
oct1712051161147
9413060030266
10130202002023
11502446aa255
1221298478973
13c37c9b0162
14643224d299
1535c0965e83
hex1e50a4e267

130202002023 has 4 divisors (see below), whose sum is σ = 173602669368. Its totient is φ = 86801334680.

The previous prime is 130202002019. The next prime is 130202002043. The reversal of 130202002023 is 320200202031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130202002023 - 22 = 130202002019 is a prime.

It is a super-2 number, since 2×1302020020232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130202001993 and 130202002011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130202002043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21700333668 + ... + 21700333673.

It is an arithmetic number, because the mean of its divisors is an integer number (43400667342).

Almost surely, 2130202002023 is an apocalyptic number.

130202002023 is a deficient number, since it is larger than the sum of its proper divisors (43400667345).

130202002023 is an equidigital number, since it uses as much as digits as its factorization.

130202002023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43400667344.

The product of its (nonzero) digits is 144, while the sum is 15.

Adding to 130202002023 its reverse (320200202031), we get a palindrome (450402204054).

The spelling of 130202002023 in words is "one hundred thirty billion, two hundred two million, two thousand, twenty-three".

Divisors: 1 3 43400667341 130202002023