Base | Representation |
---|---|
bin | 111100101000010101… |
… | …0111001101001011101 |
3 | 110110002000212101022000 |
4 | 1321100222321221131 |
5 | 4113123311123313 |
6 | 135451510112513 |
7 | 12256352333145 |
oct | 1712052715135 |
9 | 413060771260 |
10 | 130202442333 |
11 | 50244980047 |
12 | 2129864b739 |
13 | c37cb056b2 |
14 | 6432325925 |
15 | 35c0a01673 |
hex | 1e50ab9a5d |
130202442333 has 8 divisors (see below), whose sum is σ = 192892507200. Its totient is φ = 86801628204.
The previous prime is 130202442329. The next prime is 130202442361. The reversal of 130202442333 is 333244202031.
130202442333 is a `hidden beast` number, since 1 + 3 + 0 + 202 + 4 + 423 + 33 = 666.
It is not a de Polignac number, because 130202442333 - 22 = 130202442329 is a prime.
It is a super-3 number, since 3×1302024423333 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 4822312679 = 130202442333 / (1 + 3 + 0 + 2 + 0 + 2 + 4 + 4 + 2 + 3 + 3 + 3).
It is a junction number, because it is equal to n+sod(n) for n = 130202442297 and 130202442306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130202441333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2411156313 + ... + 2411156366.
It is an arithmetic number, because the mean of its divisors is an integer number (24111563400).
Almost surely, 2130202442333 is an apocalyptic number.
It is an amenable number.
130202442333 is a deficient number, since it is larger than the sum of its proper divisors (62690064867).
130202442333 is an equidigital number, since it uses as much as digits as its factorization.
130202442333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4822312688 (or 4822312682 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 27.
Adding to 130202442333 its reverse (333244202031), we get a palindrome (463446644364).
The spelling of 130202442333 in words is "one hundred thirty billion, two hundred two million, four hundred forty-two thousand, three hundred thirty-three".
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