Base | Representation |
---|---|
bin | 1011110101111011000111… |
… | …1100001001110011101111 |
3 | 1201002210120001102201000110 |
4 | 2331132301330021303233 |
5 | 3201314032442211343 |
6 | 43405440144231103 |
7 | 2512511202055161 |
oct | 275366174116357 |
9 | 51083501381013 |
10 | 13021031210223 |
11 | 417020872a273 |
12 | 156369100b493 |
13 | 735b54ba9cca |
14 | 330315260931 |
15 | 178a90beb833 |
hex | bd7b1f09cef |
13021031210223 has 16 divisors (see below), whose sum is σ = 18525475796480. Its totient is φ = 8111154262464.
The previous prime is 13021031210221. The next prime is 13021031210303. The reversal of 13021031210223 is 32201213012031.
It is not a de Polignac number, because 13021031210223 - 21 = 13021031210221 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13021031210223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13021031210221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1564647511 + ... + 1564655832.
It is an arithmetic number, because the mean of its divisors is an integer number (1157842237280).
Almost surely, 213021031210223 is an apocalyptic number.
13021031210223 is a deficient number, since it is larger than the sum of its proper divisors (5504444586257).
13021031210223 is a wasteful number, since it uses less digits than its factorization.
13021031210223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3129303438.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13021031210223 its reverse (32201213012031), we get a palindrome (45222244222254).
The spelling of 13021031210223 in words is "thirteen trillion, twenty-one billion, thirty-one million, two hundred ten thousand, two hundred twenty-three".
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