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130211053151 = 2322924722053
BaseRepresentation
bin111100101000100101…
…1101111111001011111
3110110002122001212010012
41321101023233321133
54113133012200101
6135452414433435
712256515455444
oct1712113577137
9413078055105
10130211053151
1150249821523
122129b50287b
13c38182bb5a
1464335279cb
1535c1652bbb
hex1e512efe5f

130211053151 has 8 divisors (see below), whose sum is σ = 136465738080. Its totient is φ = 124005812832.

The previous prime is 130211053111. The next prime is 130211053153. The reversal of 130211053151 is 151350112031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130211053151 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130211053153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12355760 + ... + 12366293.

It is an arithmetic number, because the mean of its divisors is an integer number (17058217260).

Almost surely, 2130211053151 is an apocalyptic number.

130211053151 is a deficient number, since it is larger than the sum of its proper divisors (6254684929).

130211053151 is a wasteful number, since it uses less digits than its factorization.

130211053151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24722305.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 130211053151 its reverse (151350112031), we get a palindrome (281561165182).

The spelling of 130211053151 in words is "one hundred thirty billion, two hundred eleven million, fifty-three thousand, one hundred fifty-one".

Divisors: 1 23 229 5267 24722053 568607219 5661350137 130211053151