Base | Representation |
---|---|
bin | 1011110101111011100000… |
… | …0101100100111101101011 |
3 | 1201002210211020111110000120 |
4 | 2331132320011210331223 |
5 | 3201314240343002133 |
6 | 43405454310534323 |
7 | 2512513563511650 |
oct | 275367005447553 |
9 | 51083736443016 |
10 | 13021134344043 |
11 | 4170260971231 |
12 | 15636bb6673a3 |
13 | 735b7037a037 |
14 | 330324c29c27 |
15 | 178a99cbeab3 |
hex | bd7b8164f6b |
13021134344043 has 32 divisors (see below), whose sum is σ = 20378980985856. Its totient is φ = 7239198054528.
The previous prime is 13021134343961. The next prime is 13021134344063. The reversal of 13021134344043 is 34044343112031.
It is not a de Polignac number, because 13021134344043 - 28 = 13021134343787 is a prime.
It is a super-2 number, since 2×130211343440432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13021134343995 and 13021134344013.
It is not an unprimeable number, because it can be changed into a prime (13021134344063) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16031805 + ... + 16824417.
It is an arithmetic number, because the mean of its divisors is an integer number (636843155808).
Almost surely, 213021134344043 is an apocalyptic number.
13021134344043 is a deficient number, since it is larger than the sum of its proper divisors (7357846641813).
13021134344043 is a wasteful number, since it uses less digits than its factorization.
13021134344043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 813803.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13021134344043 its reverse (34044343112031), we get a palindrome (47065477456074).
The spelling of 13021134344043 in words is "thirteen trillion, twenty-one billion, one hundred thirty-four million, three hundred forty-four thousand, forty-three".
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