Base | Representation |
---|---|
bin | 11000010000010000… |
… | …00001000011101111 |
3 | 1020121110201120100021 |
4 | 30020020001003233 |
5 | 203131413033403 |
6 | 5552025543011 |
7 | 640451360512 |
oct | 141010010357 |
9 | 36543646307 |
10 | 13021221103 |
11 | 558215a160 |
12 | 2634944a67 |
13 | 12c68c1b77 |
14 | 8b74d0d79 |
15 | 5132448bd |
hex | 3082010ef |
13021221103 has 4 divisors (see below), whose sum is σ = 14204968488. Its totient is φ = 11837473720.
The previous prime is 13021221091. The next prime is 13021221133. The reversal of 13021221103 is 30112212031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13021221103 - 25 = 13021221071 is a prime.
It is a super-3 number, since 3×130212211033 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13021221133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591873676 + ... + 591873697.
It is an arithmetic number, because the mean of its divisors is an integer number (3551242122).
Almost surely, 213021221103 is an apocalyptic number.
13021221103 is a deficient number, since it is larger than the sum of its proper divisors (1183747385).
13021221103 is a wasteful number, since it uses less digits than its factorization.
13021221103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1183747384.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 13021221103 its reverse (30112212031), we get a palindrome (43133433134).
The spelling of 13021221103 in words is "thirteen billion, twenty-one million, two hundred twenty-one thousand, one hundred three".
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