Base | Representation |
---|---|
bin | 10010111100101101000… |
… | …100011101001000101010 |
3 | 11121111000202122022201122 |
4 | 102330231010131020222 |
5 | 132313231043431242 |
6 | 2434105115215242 |
7 | 163035011601533 |
oct | 22745504351052 |
9 | 4544022568648 |
10 | 1302131233322 |
11 | 46225a153347 |
12 | 190441147522 |
13 | 95a377cc74a |
14 | 4704864568a |
15 | 23d110abad2 |
hex | 12f2d11d22a |
1302131233322 has 4 divisors (see below), whose sum is σ = 1953196849986. Its totient is φ = 651065616660.
The previous prime is 1302131233303. The next prime is 1302131233343. The reversal of 1302131233322 is 2233321312031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1300035516481 + 2095716841 = 1140191^2 + 45779^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1302131233291 and 1302131233300.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325532808329 + ... + 325532808332.
Almost surely, 21302131233322 is an apocalyptic number.
1302131233322 is a deficient number, since it is larger than the sum of its proper divisors (651065616664).
1302131233322 is an equidigital number, since it uses as much as digits as its factorization.
1302131233322 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 651065616663.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 1302131233322 its reverse (2233321312031), we get a palindrome (3535452545353).
The spelling of 1302131233322 in words is "one trillion, three hundred two billion, one hundred thirty-one million, two hundred thirty-three thousand, three hundred twenty-two".
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