Base | Representation |
---|---|
bin | 1011110101111100010010… |
… | …0101011100011101001101 |
3 | 1201002211100212001022101121 |
4 | 2331133010211130131031 |
5 | 3201320203032240042 |
6 | 43405531201040541 |
7 | 2512522020664642 |
oct | 275370445343515 |
9 | 51084325038347 |
10 | 13021344024397 |
11 | 4170359266185 |
12 | 1563759926151 |
13 | 735ba4943557 |
14 | 330344a0bdc9 |
15 | 178aad3dc367 |
hex | bd7c495c74d |
13021344024397 has 4 divisors (see below), whose sum is σ = 13021636676796. Its totient is φ = 13021051372000.
The previous prime is 13021344024319. The next prime is 13021344024407. The reversal of 13021344024397 is 79342044312031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4229846242281 + 8791497782116 = 2056659^2 + 2965046^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13021344024397 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13021344004397) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146259448 + ... + 146348449.
It is an arithmetic number, because the mean of its divisors is an integer number (3255409169199).
Almost surely, 213021344024397 is an apocalyptic number.
It is an amenable number.
13021344024397 is a deficient number, since it is larger than the sum of its proper divisors (292652399).
13021344024397 is an equidigital number, since it uses as much as digits as its factorization.
13021344024397 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 292652398.
The product of its (nonzero) digits is 435456, while the sum is 43.
The spelling of 13021344024397 in words is "thirteen trillion, twenty-one billion, three hundred forty-four million, twenty-four thousand, three hundred ninety-seven".
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