Search a number
-
+
13021344024397 = 44501292607897
BaseRepresentation
bin1011110101111100010010…
…0101011100011101001101
31201002211100212001022101121
42331133010211130131031
53201320203032240042
643405531201040541
72512522020664642
oct275370445343515
951084325038347
1013021344024397
114170359266185
121563759926151
13735ba4943557
14330344a0bdc9
15178aad3dc367
hexbd7c495c74d

13021344024397 has 4 divisors (see below), whose sum is σ = 13021636676796. Its totient is φ = 13021051372000.

The previous prime is 13021344024319. The next prime is 13021344024407. The reversal of 13021344024397 is 79342044312031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4229846242281 + 8791497782116 = 2056659^2 + 2965046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13021344024397 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13021344004397) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146259448 + ... + 146348449.

It is an arithmetic number, because the mean of its divisors is an integer number (3255409169199).

Almost surely, 213021344024397 is an apocalyptic number.

It is an amenable number.

13021344024397 is a deficient number, since it is larger than the sum of its proper divisors (292652399).

13021344024397 is an equidigital number, since it uses as much as digits as its factorization.

13021344024397 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 292652398.

The product of its (nonzero) digits is 435456, while the sum is 43.

The spelling of 13021344024397 in words is "thirteen trillion, twenty-one billion, three hundred forty-four million, twenty-four thousand, three hundred ninety-seven".

Divisors: 1 44501 292607897 13021344024397