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13021402103 = 83719155537
BaseRepresentation
bin11000010000010001…
…01101001111110111
31020121111001202121222
430020020231033313
5203131434331403
65552033500555
7640453043303
oct141010551767
936544052558
1013021402103
115582273146
122634a1175b
1312c6956378
148b753ad03
1551327d338
hex30822d3f7

13021402103 has 4 divisors (see below), whose sum is σ = 13021641360. Its totient is φ = 13021162848.

The previous prime is 13021402087. The next prime is 13021402133. The reversal of 13021402103 is 30120412031.

13021402103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13021402103 - 24 = 13021402087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13021402133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5951 + ... + 161487.

It is an arithmetic number, because the mean of its divisors is an integer number (3255410340).

Almost surely, 213021402103 is an apocalyptic number.

13021402103 is a deficient number, since it is larger than the sum of its proper divisors (239257).

13021402103 is an equidigital number, since it uses as much as digits as its factorization.

13021402103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 239256.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13021402103 its reverse (30120412031), we get a palindrome (43141814134).

The spelling of 13021402103 in words is "thirteen billion, twenty-one million, four hundred two thousand, one hundred three".

Divisors: 1 83719 155537 13021402103