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13022002201303 = 59613618227897
BaseRepresentation
bin1011110101111110101111…
…0100001100001011010111
31201002220001201112011101001
42331133223310030023113
53201323030030420203
643410120352044131
72512544232256024
oct275375364141327
951086051464331
1013022002201303
11417066683a237
121563902233647
13735c7b0cb344
143303a81ba54b
15178aeb09c91d
hexbd7ebd0c2d7

13022002201303 has 8 divisors (see below), whose sum is σ = 13459807780560. Its totient is φ = 12591433078080.

The previous prime is 13022002201289. The next prime is 13022002201363. The reversal of 13022002201303 is 30310220022031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13022002201303 - 221 = 13022000104151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13022002201363) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1809110350 + ... + 1809117547.

It is an arithmetic number, because the mean of its divisors is an integer number (1682475972570).

Almost surely, 213022002201303 is an apocalyptic number.

13022002201303 is a deficient number, since it is larger than the sum of its proper divisors (437805579257).

13022002201303 is an equidigital number, since it uses as much as digits as its factorization.

13022002201303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3618228017.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 13022002201303 its reverse (30310220022031), we get a palindrome (43332222223334).

The spelling of 13022002201303 in words is "thirteen trillion, twenty-two billion, two million, two hundred one thousand, three hundred three".

Divisors: 1 59 61 3599 3618227897 213475445923 220711901717 13022002201303