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13022011221 = 34340670407
BaseRepresentation
bin11000010000010110…
…00001111101010101
31020121112012201011220
430020023001331111
5203132113324341
65552054520553
7640461161202
oct141013017525
936545181156
1013022011221
11558264984a
122635066159
1312c6b0a6ab
148b7658ca9
1551334da66
hex3082c1f55

13022011221 has 4 divisors (see below), whose sum is σ = 17362681632. Its totient is φ = 8681340812.

The previous prime is 13022011207. The next prime is 13022011231. The reversal of 13022011221 is 12211022031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13022011221 - 29 = 13022010709 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13022011221.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13022011231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170335201 + ... + 2170335206.

It is an arithmetic number, because the mean of its divisors is an integer number (4340670408).

Almost surely, 213022011221 is an apocalyptic number.

It is an amenable number.

13022011221 is a deficient number, since it is larger than the sum of its proper divisors (4340670411).

13022011221 is an equidigital number, since it uses as much as digits as its factorization.

13022011221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4340670410.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 13022011221 its reverse (12211022031), we get a palindrome (25233033252).

The spelling of 13022011221 in words is "thirteen billion, twenty-two million, eleven thousand, two hundred twenty-one".

Divisors: 1 3 4340670407 13022011221