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130220211333 = 3358791209809
BaseRepresentation
bin111100101000110111…
…0101011110010000101
3110110010021022010210010
41321101232223302011
54113142333230313
6135453343020433
712256656350622
oct1712156536205
9413107263703
10130220211333
1150253a07173
12212a259a719
13c3836b74b4
14643482d349
1535c23614c3
hex1e51babc85

130220211333 has 8 divisors (see below), whose sum is σ = 173631931200. Its totient is φ = 86810982848.

The previous prime is 130220211311. The next prime is 130220211377. The reversal of 130220211333 is 333112022031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130220211333 - 212 = 130220207237 is a prime.

It is a super-2 number, since 2×1302202113332 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130220211833) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 497268 + ... + 712541.

It is an arithmetic number, because the mean of its divisors is an integer number (21703991400).

Almost surely, 2130220211333 is an apocalyptic number.

It is an amenable number.

130220211333 is a deficient number, since it is larger than the sum of its proper divisors (43411719867).

130220211333 is a wasteful number, since it uses less digits than its factorization.

130220211333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1245691.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 130220211333 its reverse (333112022031), we get a palindrome (463332233364).

The spelling of 130220211333 in words is "one hundred thirty billion, two hundred twenty million, two hundred eleven thousand, three hundred thirty-three".

Divisors: 1 3 35879 107637 1209809 3629427 43406737111 130220211333