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13022032230111 = 34340677410037
BaseRepresentation
bin1011110101111110110110…
…0110101111011011011111
31201002220010211000210011010
42331133231212233123133
53201323110222330421
643410123343430303
72512545045434412
oct275375546573337
951086124023133
1013022032230111
11417068178a333
1215639102b5393
13735c843b3478
143303ac195b79
15178aeda30076
hexbd7ed9af6df

13022032230111 has 4 divisors (see below), whose sum is σ = 17362709640152. Its totient is φ = 8681354820072.

The previous prime is 13022032230071. The next prime is 13022032230127. The reversal of 13022032230111 is 11103223022031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13022032230111 - 214 = 13022032213727 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13022032230131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170338705016 + ... + 2170338705021.

It is an arithmetic number, because the mean of its divisors is an integer number (4340677410038).

Almost surely, 213022032230111 is an apocalyptic number.

13022032230111 is a deficient number, since it is larger than the sum of its proper divisors (4340677410041).

13022032230111 is an equidigital number, since it uses as much as digits as its factorization.

13022032230111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4340677410040.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13022032230111 its reverse (11103223022031), we get a palindrome (24125255252142).

The spelling of 13022032230111 in words is "thirteen trillion, twenty-two billion, thirty-two million, two hundred thirty thousand, one hundred eleven".

Divisors: 1 3 4340677410037 13022032230111