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1302213232113 = 3434071077371
BaseRepresentation
bin10010111100110001111…
…101010000010111110001
311121111020110221021220220
4102330301331100113301
5132313413041411423
62434121204523253
7163040025561213
oct22746175202761
94544213837826
101302213232113
114622a146a242
121904646b0529
1395a4b7ac841
14470554ac5b3
1523d183a79e3
hex12f31f505f1

1302213232113 has 4 divisors (see below), whose sum is σ = 1736284309488. Its totient is φ = 868142154740.

The previous prime is 1302213231971. The next prime is 1302213232123. The reversal of 1302213232113 is 3112323122031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1302213232113 - 210 = 1302213231089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1302213232123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217035538683 + ... + 217035538688.

It is an arithmetic number, because the mean of its divisors is an integer number (434071077372).

Almost surely, 21302213232113 is an apocalyptic number.

It is an amenable number.

1302213232113 is a deficient number, since it is larger than the sum of its proper divisors (434071077375).

1302213232113 is an equidigital number, since it uses as much as digits as its factorization.

1302213232113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434071077374.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 1302213232113 its reverse (3112323122031), we get a palindrome (4414536354144).

The spelling of 1302213232113 in words is "one trillion, three hundred two billion, two hundred thirteen million, two hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 3 434071077371 1302213232113