13022210321207 has 4 divisors (see below), whose sum is σ = 13242925750440. Its totient is φ = 12801494891976.

The previous prime is 13022210321171. The next prime is 13022210321209. The reversal of 13022210321207 is 70212301222031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13022210321207 - 2¹² = 13022210317111 is a prime.

It is a super-3 number, since 3×13022210321207³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13022210321209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110357714528 + ... + 110357714645.

It is an arithmetic number, because the mean of its divisors is an integer number (3310731437610).

Almost surely, 2^{13022210321207} is an apocalyptic number.

13022210321207 is a deficient number, since it is larger than the sum of its proper divisors (220715429233).

13022210321207 is an equidigital number, since it uses as much as digits as its factorization.

13022210321207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 220715429232.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 13022210321207 its reverse (70212301222031), we get a palindrome (83234511543238).

The spelling of 13022210321207 in words is "thirteen trillion, twenty-two billion, two hundred ten million, three hundred twenty-one thousand, two hundred seven".