Base | Representation |
---|---|
bin | 111100101000111101… |
… | …1110001001111010101 |
3 | 110110010111202102011110 |
4 | 1321101323301033111 |
5 | 4113144223012212 |
6 | 135453544325233 |
7 | 12260030455362 |
oct | 1712173611725 |
9 | 413114672143 |
10 | 130223641557 |
11 | 5025593a369 |
12 | 212a3773819 |
13 | c384318909 |
14 | 6435083469 |
15 | 35c27dca3c |
hex | 1e51ef13d5 |
130223641557 has 16 divisors (see below), whose sum is σ = 181436330880. Its totient is φ = 82924007232.
The previous prime is 130223641543. The next prime is 130223641567. The reversal of 130223641557 is 755146322031.
It is not a de Polignac number, because 130223641557 - 211 = 130223639509 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130223641507) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1282038 + ... + 1379879.
It is an arithmetic number, because the mean of its divisors is an integer number (11339770680).
Almost surely, 2130223641557 is an apocalyptic number.
It is an amenable number.
130223641557 is a deficient number, since it is larger than the sum of its proper divisors (51212689323).
130223641557 is a wasteful number, since it uses less digits than its factorization.
130223641557 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2662652.
The product of its (nonzero) digits is 151200, while the sum is 39.
Adding to 130223641557 its reverse (755146322031), we get a palindrome (885369963588).
The spelling of 130223641557 in words is "one hundred thirty billion, two hundred twenty-three million, six hundred forty-one thousand, five hundred fifty-seven".
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