Base | Representation |
---|---|
bin | 11101100111001001000010… |
… | …110111001001100000000011 |
3 | 122002010011110001121111111121 |
4 | 131213021002313021200003 |
5 | 114032214412221234103 |
6 | 1140552134110453111 |
7 | 36301014056656003 |
oct | 3547110267114003 |
9 | 562104401544447 |
10 | 130233120102403 |
11 | 3855061314458a |
12 | 12734074504197 |
13 | 5788c134b2396 |
14 | 2423460c36003 |
15 | 100c9e05116bd |
hex | 767242dc9803 |
130233120102403 has 4 divisors (see below), whose sum is σ = 130372109559160. Its totient is φ = 130094130645648.
The previous prime is 130233120102383. The next prime is 130233120102469. The reversal of 130233120102403 is 304201021332031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130233120102403 - 29 = 130233120101891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130233120102703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69494726973 + ... + 69494728846.
It is an arithmetic number, because the mean of its divisors is an integer number (32593027389790).
Almost surely, 2130233120102403 is an apocalyptic number.
130233120102403 is a deficient number, since it is larger than the sum of its proper divisors (138989456757).
130233120102403 is an equidigital number, since it uses as much as digits as its factorization.
130233120102403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138989456756.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 130233120102403 its reverse (304201021332031), we get a palindrome (434434141434434).
The spelling of 130233120102403 in words is "one hundred thirty trillion, two hundred thirty-three billion, one hundred twenty million, one hundred two thousand, four hundred three".
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