Base | Representation |
---|---|
bin | 10010111100111001000… |
… | …011100010110101011001 |
3 | 11121111112210000122022121 |
4 | 102330321003202311121 |
5 | 132314134033233423 |
6 | 2434141101221241 |
7 | 163043003036365 |
oct | 22747103426531 |
9 | 4544483018277 |
10 | 1302332321113 |
11 | 4623527095aa |
12 | 190498561821 |
13 | 95a6a377bc5 |
14 | 4706722c2a5 |
15 | 23d23a7d45d |
hex | 12f390e2d59 |
1302332321113 has 4 divisors (see below), whose sum is σ = 1302335676880. Its totient is φ = 1302328965348.
The previous prime is 1302332321099. The next prime is 1302332321123. The reversal of 1302332321113 is 3111232332031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302332321113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1302332321123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1006095 + ... + 1901812.
It is an arithmetic number, because the mean of its divisors is an integer number (325583919220).
Almost surely, 21302332321113 is an apocalyptic number.
It is an amenable number.
1302332321113 is a deficient number, since it is larger than the sum of its proper divisors (3355767).
1302332321113 is an equidigital number, since it uses as much as digits as its factorization.
1302332321113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3355766.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1302332321113 its reverse (3111232332031), we get a palindrome (4413564653144).
The spelling of 1302332321113 in words is "one trillion, three hundred two billion, three hundred thirty-two million, three hundred twenty-one thousand, one hundred thirteen".
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