Base | Representation |
---|---|
bin | 10010111100111001000… |
… | …110101000100101101001 |
3 | 11121111112211112210102121 |
4 | 102330321012220211221 |
5 | 132314134240143423 |
6 | 2434141130431241 |
7 | 163043012652040 |
oct | 22747106504551 |
9 | 4544484483377 |
10 | 1302333131113 |
11 | 462353112123 |
12 | 190498892521 |
13 | 95a6a59c7b1 |
14 | 4706739d557 |
15 | 23d23b8d45d |
hex | 12f391a8969 |
1302333131113 has 16 divisors (see below), whose sum is σ = 1499329522944. Its totient is φ = 1108074862080.
The previous prime is 1302333131111. The next prime is 1302333131149. The reversal of 1302333131113 is 3111313332031.
It is a cyclic number.
It is not a de Polignac number, because 1302333131113 - 21 = 1302333131111 is a prime.
It is a super-3 number, since 3×13023331311133 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1302333131111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26536908 + ... + 26585938.
It is an arithmetic number, because the mean of its divisors is an integer number (93708095184).
Almost surely, 21302333131113 is an apocalyptic number.
It is an amenable number.
1302333131113 is a deficient number, since it is larger than the sum of its proper divisors (196996391831).
1302333131113 is a wasteful number, since it uses less digits than its factorization.
1302333131113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76872.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 1302333131113 its reverse (3111313332031), we get a palindrome (4413646463144).
The spelling of 1302333131113 in words is "one trillion, three hundred two billion, three hundred thirty-three million, one hundred thirty-one thousand, one hundred thirteen".
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