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1302333131113 = 71372769749031
BaseRepresentation
bin10010111100111001000…
…110101000100101101001
311121111112211112210102121
4102330321012220211221
5132314134240143423
62434141130431241
7163043012652040
oct22747106504551
94544484483377
101302333131113
11462353112123
12190498892521
1395a6a59c7b1
144706739d557
1523d23b8d45d
hex12f391a8969

1302333131113 has 16 divisors (see below), whose sum is σ = 1499329522944. Its totient is φ = 1108074862080.

The previous prime is 1302333131111. The next prime is 1302333131149. The reversal of 1302333131113 is 3111313332031.

It is a cyclic number.

It is not a de Polignac number, because 1302333131113 - 21 = 1302333131111 is a prime.

It is a super-3 number, since 3×13023331311133 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1302333131111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26536908 + ... + 26585938.

It is an arithmetic number, because the mean of its divisors is an integer number (93708095184).

Almost surely, 21302333131113 is an apocalyptic number.

It is an amenable number.

1302333131113 is a deficient number, since it is larger than the sum of its proper divisors (196996391831).

1302333131113 is a wasteful number, since it uses less digits than its factorization.

1302333131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76872.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1302333131113 its reverse (3111313332031), we get a palindrome (4413646463144).

The spelling of 1302333131113 in words is "one trillion, three hundred two billion, three hundred thirty-three million, one hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 7 137 959 27697 49031 193879 343217 3794489 6717247 26561423 47020729 1358011607 9506081249 186047590159 1302333131113