Base | Representation |
---|---|
bin | 10010111100111001101… |
… | …001000000110111001001 |
3 | 11121111120110111200000020 |
4 | 102330321221000313021 |
5 | 132314144042042213 |
6 | 2434142051531053 |
7 | 163043152366032 |
oct | 22747151006711 |
9 | 4544513450006 |
10 | 1302342143433 |
11 | 462358208221 |
12 | 19049b8b9a89 |
13 | 95a6c406926 |
14 | 47068667a89 |
15 | 23d2486d923 |
hex | 12f39a40dc9 |
1302342143433 has 16 divisors (see below), whose sum is σ = 1789196566080. Its totient is φ = 842010780096.
The previous prime is 1302342143411. The next prime is 1302342143437. The reversal of 1302342143433 is 3343412432031.
It is a happy number.
It is not a de Polignac number, because 1302342143433 - 221 = 1302340046281 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1302342143394 and 1302342143403.
It is not an unprimeable number, because it can be changed into a prime (1302342143437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19074738 + ... + 19142891.
It is an arithmetic number, because the mean of its divisors is an integer number (111824785380).
Almost surely, 21302342143433 is an apocalyptic number.
It is an amenable number.
1302342143433 is a deficient number, since it is larger than the sum of its proper divisors (486854422647).
1302342143433 is a wasteful number, since it uses less digits than its factorization.
1302342143433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38217976.
The product of its (nonzero) digits is 62208, while the sum is 33.
Adding to 1302342143433 its reverse (3343412432031), we get a palindrome (4645754575464).
The spelling of 1302342143433 in words is "one trillion, three hundred two billion, three hundred forty-two million, one hundred forty-three thousand, four hundred thirty-three".
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