13023471816213 has 4 divisors (see below), whose sum is σ = 17364629088288. Its totient is φ = 8682314544140.

The previous prime is 13023471816107. The next prime is 13023471816239. The reversal of 13023471816213 is 31261817432031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13023471816213 - 2¹³ = 13023471808021 is a prime.

It is a super-2 number, since 2×13023471816213² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13023471816613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170578636033 + ... + 2170578636038.

It is an arithmetic number, because the mean of its divisors is an integer number (4341157272072).

Almost surely, 2^{13023471816213} is an apocalyptic number.

It is an amenable number.

13023471816213 is a deficient number, since it is larger than the sum of its proper divisors (4341157272075).

13023471816213 is an equidigital number, since it uses as much as digits as its factorization.

13023471816213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4341157272074.

The product of its (nonzero) digits is 145152, while the sum is 42.

The spelling of 13023471816213 in words is "thirteen trillion, twenty-three billion, four hundred seventy-one million, eight hundred sixteen thousand, two hundred thirteen".