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130241225335 = 5132003711159
BaseRepresentation
bin111100101001011111…
…0110110001001110111
3110110011201211202120111
41321102332312021313
54113213223202320
6135455413243451
712260333102134
oct1712276661167
9413151752514
10130241225335
115026485a311
12212a9633587
13c387b64310
14643753d58b
1535c4112a5a
hex1e52fb6277

130241225335 has 8 divisors (see below), whose sum is σ = 168311737440. Its totient is φ = 96178135584.

The previous prime is 130241225243. The next prime is 130241225339. The reversal of 130241225335 is 533522142031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130241225335 - 27 = 130241225207 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130241225297 and 130241225306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130241225339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1001855515 + ... + 1001855644.

It is an arithmetic number, because the mean of its divisors is an integer number (21038967180).

Almost surely, 2130241225335 is an apocalyptic number.

130241225335 is a deficient number, since it is larger than the sum of its proper divisors (38070512105).

130241225335 is a wasteful number, since it uses less digits than its factorization.

130241225335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2003711177.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 130241225335 its reverse (533522142031), we get a palindrome (663763367366).

The spelling of 130241225335 in words is "one hundred thirty billion, two hundred forty-one million, two hundred twenty-five thousand, three hundred thirty-five".

Divisors: 1 5 13 65 2003711159 10018555795 26048245067 130241225335