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1302421114343 = 1518625305393
BaseRepresentation
bin10010111100111110010…
…110010000110111100111
311121111202222002210201202
4102330332112100313213
5132314324301124333
62434153552313115
7163045131544646
oct22747626206747
94544688083652
101302421114343
11462398846238
1219050224279b
1395a8289678b
1447074d4335d
1523d2b76c5e8
hex12f3e590de7

1302421114343 has 4 divisors (see below), whose sum is σ = 1311046419888. Its totient is φ = 1293795808800.

The previous prime is 1302421114331. The next prime is 1302421114373. The reversal of 1302421114343 is 3434111242031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1302421114343 - 24 = 1302421114327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1302421114373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4312652546 + ... + 4312652847.

It is an arithmetic number, because the mean of its divisors is an integer number (327761604972).

Almost surely, 21302421114343 is an apocalyptic number.

1302421114343 is a deficient number, since it is larger than the sum of its proper divisors (8625305545).

1302421114343 is an equidigital number, since it uses as much as digits as its factorization.

1302421114343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8625305544.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1302421114343 its reverse (3434111242031), we get a palindrome (4736532356374).

The spelling of 1302421114343 in words is "one trillion, three hundred two billion, four hundred twenty-one million, one hundred fourteen thousand, three hundred forty-three".

Divisors: 1 151 8625305393 1302421114343