Base | Representation |
---|---|
bin | 11101100111010010101001… |
… | …000011000101111001100010 |
3 | 122002011011001012001021211001 |
4 | 131213102221003011321202 |
5 | 114032402013124202002 |
6 | 1141001000404342214 |
7 | 36301530321302152 |
oct | 3547225103057142 |
9 | 562134035037731 |
10 | 130243424444002 |
11 | 38554a20728981 |
12 | 1273606b3a496a |
13 | 5789b9625a82c |
14 | 2423b5b57c762 |
15 | 100cde4e89a87 |
hex | 7674a90c5e62 |
130243424444002 has 4 divisors (see below), whose sum is σ = 195365136666006. Its totient is φ = 65121712222000.
The previous prime is 130243424443963. The next prime is 130243424444047. The reversal of 130243424444002 is 200444424342031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 122203539994041 + 8039884449961 = 11054571^2 + 2835469^2 .
It is a super-2 number, since 2×1302434244440022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32560856110999 + ... + 32560856111002.
Almost surely, 2130243424444002 is an apocalyptic number.
130243424444002 is a deficient number, since it is larger than the sum of its proper divisors (65121712222004).
130243424444002 is an equidigital number, since it uses as much as digits as its factorization.
130243424444002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65121712222003.
The product of its (nonzero) digits is 294912, while the sum is 37.
Adding to 130243424444002 its reverse (200444424342031), we get a palindrome (330687848786033).
The spelling of 130243424444002 in words is "one hundred thirty trillion, two hundred forty-three billion, four hundred twenty-four million, four hundred forty-four thousand, two".
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