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130243424444002 = 265121712222001
BaseRepresentation
bin11101100111010010101001…
…000011000101111001100010
3122002011011001012001021211001
4131213102221003011321202
5114032402013124202002
61141001000404342214
736301530321302152
oct3547225103057142
9562134035037731
10130243424444002
1138554a20728981
121273606b3a496a
135789b9625a82c
142423b5b57c762
15100cde4e89a87
hex7674a90c5e62

130243424444002 has 4 divisors (see below), whose sum is σ = 195365136666006. Its totient is φ = 65121712222000.

The previous prime is 130243424443963. The next prime is 130243424444047. The reversal of 130243424444002 is 200444424342031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 122203539994041 + 8039884449961 = 11054571^2 + 2835469^2 .

It is a super-2 number, since 2×1302434244440022 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32560856110999 + ... + 32560856111002.

Almost surely, 2130243424444002 is an apocalyptic number.

130243424444002 is a deficient number, since it is larger than the sum of its proper divisors (65121712222004).

130243424444002 is an equidigital number, since it uses as much as digits as its factorization.

130243424444002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65121712222003.

The product of its (nonzero) digits is 294912, while the sum is 37.

Adding to 130243424444002 its reverse (200444424342031), we get a palindrome (330687848786033).

The spelling of 130243424444002 in words is "one hundred thirty trillion, two hundred forty-three billion, four hundred twenty-four million, four hundred forty-four thousand, two".

Divisors: 1 2 65121712222001 130243424444002